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Question

Two tuning forks A and B produce notes of frequencies 336 Hz and 340 Hz respectively. An unknown note of guitar string when sounded with fork A produce certain beats. When the same note is sounded with fork B, the beat frequency gets doubled. The unknown note of guitar string is -

( the frequency of guitar string is less than that of A and B )

A
332 Hz
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B
340 Hz
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C
344 Hz
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D
348 Hz
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Solution

The correct option is A 332 Hz
nA=336 Hz

nB=340 Hz

Let unknown frequency is n.

It produces Δn beats with A.

nAn=Δn ...(I)

nBn=2Δn ...(II)

Subtracting I from II,

nBnA=Δn

340336=Δn

Δn=4

Now,

n=nAΔn

n=3364=332 Hz

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