Two tuning forks A, B vibrate with frequencies in the ratio 2 : 7 and their wavelength in the ratio 3 : 4 respectively. Find the tuning fork producing greater velocity of sound.

Tuning fork A

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Tuning fork B

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Both (A) and (B)

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Cannot be determined

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Solution

The correct option is D Tuning fork B
We know that, $v = u λ$ , where $v$ is the speed of sound wave, $u$ is the frequency.

Now

Let, $v_{A}$ and $v_{B}$ are the speed of tuning fork A and B.

then, $v_{A} / v_{B} = u_{A} / u_{B} * λ_{A} / λ_{B}$

We get, $v_{A} / v_{B} = 6 / 28$

Therefor, we get $v_{B} > v_{A}$

Hence, Velocity of Sound is greater in Fork $B$

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Two tuning forks A, B vibrate with frequencies in the ratio 2 : 7 and their wavelength in the ratio 3 : 4 respectively. Find the tuning fork producing greater velocity of sound.

The correct option is D Tuning fork BWe know that, v=uλ, where v is the speed of sound wave, u is the frequency.NowLet, vA and vB are the speed of tuning fork A and B.then, vA/vB=uA/uB∗λA/λBWe get, vA/vB=6/28Therefor, we get vB>vAHence, Velocity of Sound is greater in Fork B