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Beat Frequency

Two tuning fo...

Question

Two tuning forks give 4 beats per second when sounded simultaneously. The frequency of one of the fork is 384 Hz. When the other fork is loaded with a little wax 6 beats per second are produced. The frequency of the second fork is

A

380 Hz

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B

370 Hz

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C

388 Hz

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D

350 Hz

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Solution

The correct option is A 380 Hz
Frequency of fork one is $384 H_{z}$ .
When other fork is waxed beats is increased.
So, frequency of other fork is less than frequency of fork one.
So, beat $=$ frequency of fork one $-$ frequency of second fork
$4 = 384 -$ Frequency of second fork
Frequency of second fork $= 380 H_{z}$

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