Two tuning forks have frequencies 450 Hz and 454 Hz respectively. On sounding these forks together, the time interval between successive maximum intensities will be

1/4 sec

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1/2 sec

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1 sec

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2 sec

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Solution

The correct option is A 1/4 sec
The time interval between successive maximum intensities will be $\frac{1}{n_{1} \sim n_{2}} = \frac{1}{454 - 450} = \frac{1}{4}$ sec

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Two tuning forks have frequencies 450 Hz and 454 Hz respectively. On sounding these forks together, the time interval between successive maximum intensities will be

The correct option is A 1/4 sec The time interval between successive maximum intensities will be 1n1∼ n2=1454−450=14 sec

The correct option is A 1/4 sec
The time interval between successive maximum intensities will be $\frac{1}{n_{1} \sim n_{2}} = \frac{1}{454 - 450} = \frac{1}{4}$ sec