Two tuning forks when sounded together produced a beat with frequency of 4 Hz. The frequency of one fork is 256 Hz. The number of beats heard increases when the fork of frequency 256 Hz is loaded with wax. The frequency of the other fork is,

504

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520

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260

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252

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Solution

The correct option is C
260

$256$ - $n_{2}$ = 4 or $n_{2}$ - $256$ = $4$

As the number of beats increases; $n_{2}$ = $260 H z$

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