Question

Two types of carbon-carbon covalent bond lengths are present in:

• A. Diamond
• B. graphite
• C. $C_{60}$
• D. benzene

Answer 1

Answer: (A)

Diamond

Diamond has all carbon atoms in $s{p}^3$

$\therefore$ same $B.L$

Graphite has all carbon atoms in $s{p}^2$ and conjugation

$\therefore$ Same $B.L$

$C_{60}$ has same carbon in $s{p}_2$, some in $s{p}^3$

$\therefore$ different $B.L$

Benzene has conjugation and all carbon $s{p}^2$

Same $B.L$