Question

Two unbiased dice are rolled once. Find the probability of getting a doublet.

• A. $\frac{1}{6}$
• B. $\frac{3}{4}$
• C. $\frac{2}{3}$
• D. $\frac{1}{5}$

Answer 1

The correct option is A $\frac{1}{6}$

If two dice are rolled, then number of sample space is $n\left(S\right)=6\times 6=36$

Let $E$ be the event of getting doublet, so $E=\left\{\right(1,1),(2,2),(3,3),(4,4),(5,5),(6,6\left)\right\}$

So, $n\left(E\right)=6$

Hence, required probability $=\frac{n\left(E\right)}{n\left(S\right)}=\frac{6}{36}=\frac{1}{6}$