Question

Two unbiased dice are rolled once. Find the probability of getting difference greater than $4$.

• A. $\frac{1}{6}$
• B. $\frac{3}{4}$
• C. $\frac{1}{2}$
• D. $\frac{1}{18}$

Answer 1

Answer: (D)

$\frac{1}{18}$

When two unbiased dice are rolled once, the total number of possibilities or the sample space becomes $36(6$ options for each dice).

Now, since we need the difference between the two showcased values to be more than 4, we have only 2 possibilities, either the numbers on the dice could be $(1,6)$ or $(6,1)$.

$\therefore$ probability of getting the difference greater than 4 becomes $\frac{2}{36}$ i.e. $\frac{1}{18}$.