Question

Two unbiased dice are rolled once. What is the probability of getting a doublet.

Answer 1

We know that when two unbiased dice are rolled once, the total number of possible outcomes is $6\times 6=36.\therefore n\left(S\right)=36$
Let $A$ be the event of getting a doublet.
$A=\left\{\right(1,1),(2,2),(3,3),(4,4),(5,5),(6,6\left)\right\}\therefore n\left(A\right)=6$
$\therefore P\left(A\right)=\frac{n\left(A\right)}{n\left(S\right)}=\frac{6}{36}$