Two unbiased dice are rolled once. So, the possible outcomes are
S={(1,1),(1,2),...(1,6),(2,1),...(2,6),(3,1),..(3,6),.....,(6,6)}
∴n(S)=36
Let A be an event of getting a sum less than 10.
Then A={(1,1),(1,2),...(1,6),(2,1),....,(2,6),(3,1),...(3,6),(4,1),...,(4,5),(5,1),(5,4),(6,1),(6,2),(6,3)}
∴n(A)=30
∴P(A)=n(A)n(S)=3036=56
Hence, P(A)=56