CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two unequal blocks placed over each other of different densities σ1 and σ2 are immersed in a fluid of density of σ. The block of density σ1 is fully submerged and the block of density σ2 is partly submerged so that ratio of their masses is 1/2 and σ/σ1=2 and σ/σ2=0.5. Find the degree of submergence of the upper block of density σ2

A
50% submerged
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
25% submerged
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
75% submerged
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
fully submerged
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C fully submerged
Let the volumes of two blocks be V1 and V2
Let the fraction f of the second block is submerged.
Balancing weight and buoyancy,
V1σ1g+fV2σ2g=(V1+fV2)σg
also, V1σ1/V2σ2=m1/m2=1/2V2σ2=2V1σ1
V2σ2+f×2V1σ1=(V1+f×2V1σ1/σ2)σg
σ1+2fσ2=(1+2fσ1/σ2)σ
σ1/σ+2fσ1/σ=(1+2fσ1/σ2)
1/2+2f/2=(1+2f/4)
f=1
So second block is submerged completely.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Van't Hoff Factor
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon