Two unequal masses $A$ and $B$ moving along a straight line are brought to rest by equal retarding forces. If $A$ moves twice the time as $B$ but goes only $1 / 3$ of the distance covered by $B$ before coming to rest, what is the ratio of their velocities?

1:6

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6:1

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1:2

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Solution

The correct option is A 1:6
For Mass A

S1=S2/3

t1=2 .t2

For Mass B:

S=S2

t=t2

velocityA/velocityB= (S1/t1) / (S2/t2)

= (S2/3*2t2 )/ (t2/S2)

= 1:6

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Two unequal masses A and B moving along a straight line are brought to rest by equal retarding forces. If A moves twice the time as B but goes only 1/3 of the distance covered by B before coming to rest, what is the ratio of their velocities?

The correct option is A 1:6For Mass A S1=S2/3 t1=2 .t2 For Mass B: S=S2 t=t2 velocityA/velocityB= (S1/t1) / (S2/t2) = (S2/3*2t2 )/ (t2/S2) = 1:6

Two unequal masses $A$ and $B$ moving along a straight line are brought to rest by equal retarding forces. If $A$ moves twice the time as $B$ but goes only $1 / 3$ of the distance covered by $B$ before coming to rest, what is the ratio of their velocities?

The correct option is A 1:6
For Mass A

S1=S2/3

t1=2 .t2

For Mass B:

S=S2

t=t2

velocityA/velocityB= (S1/t1) / (S2/t2)

= (S2/3*2t2 )/ (t2/S2)

= 1:6