Two uniform and identical rectangular plates of dimensions a × 4a are arranged as shown in the figure to form a tee (T). The distance of the centre of mass of the system from the bottom of the tee (shown by dotted lines) is

3.5a

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3.25a

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3.75a

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Solution

The correct option is B
3.25a

$Y_{c m}$ = $\frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}}$

Here $m_{1} = m_{2}$

$Y_{c m}$ = $\frac{m_{1} (2 a) + m_{2} (4.5 a)}{2 m} = 3.25 a$

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Two uniform and identical rectangular plates of dimensions a × 4a are arranged as shown in the figure to form a tee (T). The distance of the centre of mass of the system from the bottom of the tee (shown by dotted lines) is

The correct option is B 3.25a Ycm = m1x1+m2x2m1+m2 Here m1=m2 Ycm = m1(2a)+m2(4.5a)2m=3.25a

The correct option is B
3.25a

$Y_{c m}$ = $\frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}}$

Here $m_{1} = m_{2}$

$Y_{c m}$ = $\frac{m_{1} (2 a) + m_{2} (4.5 a)}{2 m} = 3.25 a$