Question

Two uniform dice marked 1 to 6 are thrown together.The probability that the total score on them is either minimum or maximum is

• A. $\frac{4}{36}$
• B. $\frac{5}{36}$
• C. $\frac{2}{36}$
• D. $\frac{1}{36}$

Answer 1

Answer: (C)

$\frac{2}{36}$

Total cases when two dice are thrown $=6\times 6=36$
The total score on them is minimum when sum is: $2$
Minimum sum 2 would come when both dice will show $1$.
The total score on them is maximum when sum is: $36$
Maximum sum 36 would come when both dice will show $6$.
So total cases when total score on them is either minimum or maximum is: $2$
Probability that the total score on them is either minimum or maximum is$=\frac{2}{36}$