Two vectors are A- -B- and A- -B- The angle between their resultant vector and A- is-

Let the angle between vectors $\to a$ and $\to b$ is $\frac{π}{6}$ , between vectors $\to b$ and $\to c$ is $\frac{π}{4}$ and between vectors $\to c$ and $\to a$ is $\frac{π}{3}$ . The angle, the vector $\to a$ makes with the plane containing vectors $\to b$ and $\to c$ , is

Q. Two non - zero vectors

\to A

and

\to B

are such that

| \to A + \to B | = | \to A - \to B |

. Find angle between

\to A

and

\to B

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Two vectors are (→A+→B) and (→A−→B). The angle between their resultant vector and →A is:

The correct option is D zeroThe resultant of →A+→B and →A−→B is →R=(→A+→B)+(→A−→B)=2→A. Hence, angle between →R and →A = angle between 2→A and →A = zero.

Two vectors are $(\to A + \to B)$ and $(\to A - \to B)$ . The angle between their resultant vector and $\to A$ is:

The correct option is D zero
The resultant of $\to A + \to B$ and $\to A - \to B$ is $\to R = (\to A + \to B) + (\to A - \to B) = 2 \to A$ .
Hence, angle between $\to R$ and $\to A$ $=$ angle between $2 \to A$ and $\to A$ $=$ zero.