Two vectors, both equal in magnitude, have their resultant equal in magnitude to any of the two vectors. Find the angle between the vectors.

60^{\circ}

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75^{\circ}

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90^{\circ}

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120^{\circ}

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Solution

The correct option is D $120^{\circ}$
Let $θ$ be the angle between the two vectors
$∴$ $A^{2} = A^{2} + A^{2} + 2 A A cos θ$
which gives, $cos θ = - \frac{1}{2}$
$θ = 120^{\circ}$

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Two vectors, both equal in magnitude, have their resultant equal in magnitude to any of the two vectors. Find the angle between the vectors.

The correct option is D 120∘Let θ be the angle between the two vectors ∴ A2=A2+A2+2AAcosθ which gives, cosθ=−12 θ=120∘

The correct option is D $120^{\circ}$
Let $θ$ be the angle between the two vectors
$∴$ $A^{2} = A^{2} + A^{2} + 2 A A cos θ$
which gives, $cos θ = - \frac{1}{2}$
$θ = 120^{\circ}$