Two vectors having equal magnitude A make an angle of - with each other- find magnitude and direction of resultant-

FOR MAGNITUDE: R(Resultant vector) = √(A^2+A^2) R = √(2A^2) R = √(2)A FOR ANGLE; θ = tan^ 1(AA) θ = tan^ 1(1) θ = 45^∘ ...

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Standard XII

Physics

Vector Addition

Two vectors h...

Question

Two vectors having equal magnitude $A$ make an angle of $θ$ with each other, find magnitude and direction of resultant.

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Solution

FOR MAGNITUDE:
$R (R e s u l t a n t v e c t o r) = \sqrt{A^{2} + A^{2}}$
$R = \sqrt{2 A^{2}}$
$R = \sqrt{2} A$
FOR ANGLE;
$θ = t a n^{- 1} (\frac{A}{A})$
$θ = t a n^{- 1} (1)$
$θ = 45^{\circ}$

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Two vectors having equal magnitude A make an angle of θ with each other, find magnitude and direction of resultant.

FOR MAGNITUDE:R(Resultantvector)=√A2+A2R=√2A2R=√2AFOR ANGLE;θ=tan−1(AA)θ=tan−1(1)θ=45∘

Two vectors having equal magnitude $A$ make an angle of $θ$ with each other, find magnitude and direction of resultant.

FOR MAGNITUDE:
$R (R e s u l t a n t v e c t o r) = \sqrt{A^{2} + A^{2}}$
$R = \sqrt{2 A^{2}}$
$R = \sqrt{2} A$
FOR ANGLE;
$θ = t a n^{- 1} (\frac{A}{A})$
$θ = t a n^{- 1} (1)$
$θ = 45^{\circ}$