Two vectors A and B are related as A-2B-3A-B- lf A-6i-2k- then B-

The correct option is B #10; 24i⃗+8k⃗ Given, A⃗ 2B⃗ = 3(A⃗ +B⃗ ) Rearranging the terms we get, ⇒B⃗ = 4A⃗ ⇒B⃗ = 4(6î 2k̂ )= 24î +8k̂ ...

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Byju's Answer

Standard XII

Physics

Unit Vectors

Two vectors ...

Question

Two vectors $\to A$ and $\to B$ are related as $\to A - 2 \to B = - 3 (\to A + \to B)$ . lf $\to A = 6 \to i - 2 \to k$ , then $\to B =$

- 24 \to i + 8 \to k

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- 8 \to k - 24 \to i

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2 \to k - 6 \to i

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2 \to k + 6 \to i

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Solution

The correct option is B $- 24 \to i + 8 \to k$
Given,
$\to A - 2 \to B = - 3 (\to A + \to B)$
Rearranging the terms we get,
$\Rightarrow \to B = - 4 \to A$
$\Rightarrow \to B = - 4 (6^i - 2^k) = - 24^i + 8^k$

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Similar questions

Q. Equation of the plane through three points

A, B, C

with position vectors

- 6 \to i + 3 \to j + 2 \to k, 3 \to i - 2 \to j + 4 \to k, 5 \to i + 7 \to j + 3 \to k

Q. Taking

O

' as origin and the position vectors of

A, B

are

\to i + 3 \to j - 2 \to k, 3 \to i + \to j - 2 \to k

. The vector

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is bisecting the angle

A O B

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- - \to A B

then

C

Q. Let

\to a, \to b

and

\to c

be there non-zero vectors such that no two of these are collinear. If the vector

\to a + 2 \to b

is collinear with

\to c

and

\to b + 3 \to c

is collinear with

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then

\to a + 2 \to b + 6 \to c

equals

Q. If

3 \to i + 2 \to j + 8 \to k

and

2 \to i + x \to j + \to k

are at right angles, then

x =

A B C D E F

is a regular hexagon where centre

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Two vectors →A and →B are related as →A−2→B=−3(→A+→B). lf →A=6→i−2→k, then →B=

The correct option is B −24→i+8→kGiven,→A−2→B=−3(→A+→B)Rearranging the terms we get,⇒→B=−4→A⇒→B=−4(6^i−2^k)=−24^i+8^k

Two vectors $\to A$ and $\to B$ are related as $\to A - 2 \to B = - 3 (\to A + \to B)$ . lf $\to A = 6 \to i - 2 \to k$ , then $\to B =$

The correct option is B $- 24 \to i + 8 \to k$
Given,
$\to A - 2 \to B = - 3 (\to A + \to B)$
Rearranging the terms we get,
$\Rightarrow \to B = - 4 \to A$
$\Rightarrow \to B = - 4 (6^i - 2^k) = - 24^i + 8^k$