Question

Two very long straight, particle wires carry steady currents i and – i respectively. The distance between the wires is d. At a certain instant of time, a point charge q is at a point equidistant from the two wires, in the plane of the wires. It's instantaneous velocity $\overrightarrow{v}$ is perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is

• A. $\frac{{\mu }_{0}iqv}{2\pi d}$
• B. $\frac{{\mu }_{0}iqv}{\pi d}$
  
• C. $\frac{2{\mu }_{0}iqv}{2\pi d}$
• D. $Zero$

Answer 1

The correct option is D $Zero$

According to given information, we see that direction of magnetic field is along the direction of motion of charge. So, net force on it is zero.