Two vessels A and B have same base area. Equal volumes of a liquid are poured in the two vessels to different heights $h_{A}$ and $h_{B} (> h_{A})$ .ln which vessel, the force on the base of vessel will be more.

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Solution

Let the base area be $S$
Pressure at the bottom of the vessel $P = P_{o} + ρ g h$
$∴$ Force on the base of the vessel $F = P S = (P_{o} + ρ g h) S$
$∴$ $h_{B} > h_{A}$ $⟹$ $F_{B} > F_{A}$

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Two vessels A and B have same base area. Equal volumes of a liquid are poured in the two vessels to different heights hA and hB(>hA).ln which vessel, the force on the base of vessel will be more.

Let the base area be SPressure at the bottom of the vessel P=Po+ρgh∴ Force on the base of the vessel F=PS=(Po+ρgh)S∴ hB>hA ⟹ FB>FA

Two vessels A and B have same base area. Equal volumes of a liquid are poured in the two vessels to different heights $h_{A}$ and $h_{B} (> h_{A})$ .ln which vessel, the force on the base of vessel will be more.

Let the base area be $S$
Pressure at the bottom of the vessel $P = P_{o} + ρ g h$
$∴$ Force on the base of the vessel $F = P S = (P_{o} + ρ g h) S$
$∴$ $h_{B} > h_{A}$ $⟹$ $F_{B} > F_{A}$