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Byju's Answer

Standard XII

Chemistry

Ideal Gas Equation

Two vessels c...

Question

Two vessels connected by a valve of negligible volume. One container $(I)$ has $2.8 g$ of $N_{2}$ at temperature $T_{1} (K)$ . The other container $(I I)$ is completely evacuated. The container $(I)$ is heated to $T_{2} (K)$ while container $(I I)$ is maintained at $T_{2} / 3 (K)$ . volume of vessel $(I)$ is half that of vessel $(I I)$ . If the valve is opened then what is the weight ratio of $N_{2}$ in both vessel $(W_{I} / W_{I I})$ ?

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Solution

The correct option is C $1 : 6$
Let $x$ mole of $N_{2}$ present into vessel $I I$ and $P$ is final pressure of $N_{2}$
$P (2 V) = x R (T_{2} / 3)$ and $P (V) = (0.1 - x) R T_{2}$
$\Rightarrow 2 = \frac{x}{3 (0.1 - x)}$
$\Rightarrow x = 0.6 / 7 m o l e$ ;
$\frac{0.6}{7} \times 28 = 2.4 g N_{2}$
$I I$ has $2.4 g N_{2}$ and $I$ has $0.4 g N_{2}$ ;
$\frac{W_{I}}{W_{I I}} = \frac{0.4}{2.4} = 1 : 6$

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Similar questions

Q. Two vessels are connected by a valve of negligible volume. One container

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2.8 g

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while ontainer

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The correct option is C 1:6Let x mole of N2 present into vessel II and P is final pressure of N2P(2V)=xR(T2/3) and P(V)=(0.1−x)RT2⇒2=x3(0.1−x)⇒x=0.6/7mole;0.67×28=2.4gN2II has 2.4gN2 and I has 0.4gN2;WIWII=0.42.4=1:6