Two vessels separately contain two ideal gases A and B at the same temperature. The pressure of A is twice that of B. Under such conditions, the density of A is found to be 1.5 times the density of B. The ratio of molecular weight of A and B is
A
12
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B
23
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C
34
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D
2
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Solution
The correct option is C34 For ideal gas, PV=RT and M=ρV
thus, PMρ=RT
here, PAMAρA=RT....(1)
and PBMBρB=RT....(2) (1)/(2)⇒MAMB=ρAρB×PBPA=32×12=34