Two vessels whose volume are in the ratio $2 : 1$ contain nitrogen and oxygen at $800 m m$ and $680 m m$ pressure respectively, when they are connected together what will be the pressure of the resulting mixture?

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Solution

Applying mole conservation,
$P_{n e w} = \frac{P_{1} V_{1} + P_{2} V_{2}}{V_{t o t a l}}$
= $\frac{800 \times 2 + 680 \times 1}{3}$
= $760 m m$

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Two vessels whose volume are in the ratio 2:1 contain nitrogen and oxygen at 800 mm and 680 mm pressure respectively, when they are connected together what will be the pressure of the resulting mixture?

Applying mole conservation,Pnew=P1V1+P2V2Vtotal=800×2+680×13=760 mm

Two vessels whose volume are in the ratio $2 : 1$ contain nitrogen and oxygen at $800 m m$ and $680 m m$ pressure respectively, when they are connected together what will be the pressure of the resulting mixture?

Applying mole conservation,
$P_{n e w} = \frac{P_{1} V_{1} + P_{2} V_{2}}{V_{t o t a l}}$
= $\frac{800 \times 2 + 680 \times 1}{3}$
= $760 m m$