wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two vibrating strings of same material but lengths L and 2L have radii 2r and r respectively. They are stretched under the same tension and vibrate in their fundamental modes with frequencies f1 and f2 respectively. The ratio of f1f2 is given by (strings are fixed at both ends)

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1
Fundamental frequency for vibration is given by,
f=v2L=12LTμ
f=12LTρs, where μ=ρs
s cross - sectional area of string
s=πr2)
f1f2=r2L2r1L1=r×2L2r×L
f1f2=1

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Normal Modes on a String
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon