The correct option is B A-B interactions are stronger than A-A and B-B interactions.
A maximum boiling azeotrope is formed by non-ideal solutions showing negative deviation. Boiling point more than either of the two components so, vapour pressure is minimum at azeotropic concentration.
PT<p∘AχA+p∘BχB
Mixtures showing negative deviation from Raoult's law have solute-solvent interactions stronger than that of solute-solute and solvent-solvent interactions.
So, A-B interactions are stronger than A-A and B-B interactions.