Two voltmeters, one of copper and another of silver are joined in parallel. When a total charge $q$ flows through voltmeters, equal amount of metals are deposited. If electrochemical equivalents of $C u$ and $A g$ are $z_{1}$ and $z_{2}$ respectively then charges flows through the silver voltameter is

\frac{q}{1 + \frac{z_{2}}{z_{1}}}

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\frac{q}{1 + \frac{z_{1}}{z_{2}}}

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q \frac{z_{2}}{z_{1}}

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q \frac{z_{1}}{z_{2}}

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Solution

The correct option is A $\frac{q}{1 + \frac{z_{2}}{z_{1}}}$
$∵ m = z q$
$∵ z_{1} q_{1} = z_{2} q_{2}$

or $q_{2} = \frac{z_{1} q_{1}}{z_{2}}$ but $q = q_{1} + q_{2}$

$∵ q_{2} = \frac{z_{1}}{z_{2}} (_{1} - q_{1})$ or $q_{2} (1 + \frac{z_{1}}{z_{2}}) = \frac{z_{1}}{z_{2}} q$
or
$q_{2} = \frac{q z}{z_{1} + z_{2}}$ or $\frac{q}{1 + \frac{z_{2}}{z_{1}}}$

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Similar questions

Q. Two voltameters, one of copper and another of silver, are joined in parallel. When a total charge

q

flows through the voltameters, equal amount of metals are deposited. If the electrochemical equivalents of copper and silver are

z_{1}

and

z_{2}

respectively, the charge which flows through the silver voltameter is

Q. If

P

and

Q

are represented by the complex numbers

z_{1}

and

z_{2}

respectively, such that

∣ ∣ ∣ \frac{1}{z_{2}} + \frac{1}{z_{1}} ∣ ∣ ∣ = ∣ ∣ ∣ \frac{1}{z_{2}} - \frac{1}{z_{1}} ∣ ∣ ∣

, then

If P and Q are represented by the numbers $z_{1}$ and $z_{2}$ such that $∣ ∣ ∣ \frac{1}{z_{2}} + \frac{1}{z_{1}} ∣ ∣ ∣$ = $∣ ∣ ∣ \frac{1}{z_{2}} - \frac{1}{z_{1}} ∣ ∣ ∣$ , then the circumcentre of $△ O P Q$ ,(where O is the origin) is