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Conduction Law

Two walls of ...

Question

Two walls of same thickness and cross sectional area have thermal conductivities in the ratio $1 : 2$ . If same temperature difference is maintained across the two faces of both the walls, what is the ratio of heat flow $Q_{1} : Q_{2}$ ?

A

1 : 2

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B

1 : 1

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C

2 : 1

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D

4 : 1

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Solution

The correct option is A $1 : 2$
$Q = - k A \frac{△ T}{△ x} \frac{Q_{1}}{Q_{2}} = \frac{- k_{1} A \frac{△ T}{△ x}}{- k_{2} A \frac{△ T}{△ x}} = \frac{k_{1}}{k_{2}} = \frac{1}{2}$
( same temperature difference, same thickness, same cross-sectional area )

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