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Three Phase Two Wattmeter Method-2

Two wattmeter...

Question

Two wattmeters, which are connected to measure the total power in a three-phase system supplying a balanced load, read 10.5 kW and -2.5 kW, respectively. The total power and the power factor respectively, are

A

13.0 kW, 0.334

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B

13.0 kW, 0.684

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C

8.0 kW, 0.52

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D

8.0 kW, 0.334

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Solution

The correct option is D 8.0 kW, 0.334
$P_{1} = 10.5 k W a n d P_{2} = 02.5 k W$

$T o t a l p o w e r = P_{1} + P_{2}$
$= 10.5 - 2.5 = 8 k W$

Power factor,

$c o s ϕ = c o s (t a n^{- 1} \sqrt{3} \frac{P_{1} - P_{2}}{P_{1} + P_{2}})$

$= c o s (t a n^{- 1} \sqrt{3} \frac{10.5 - (- 2.5)}{10.5 + (- 2.5)})$

$= 0.334$

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