Two waves are represented by the equations y 1- a sin - t - kx -0-57 m and y 2- a cos - t - kx m where x is in meter and t in s- The phasedifference between them isA- 1-0 radianB- 0-57 radianC- 1-25 radianD- 1-57 radian

The correct option is A 1.0 radiany_2=a sin(ω t+kx+π/2 ) y_1=a sin(ω t+kx+0.57 ) Phase difference =(π/2 0.57 )=1 radian ...

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Mechanical & Non-Mechanical Waves

Two waves are...

Question

Two waves are represented by the equations $y_{1} = a s i n (ω t + k x + 0.57) m$ and $y_{2} = a c o s (ω t + k x) m$ where x is in meter and t in s. The phase difference between them is

0.57 radian

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1.0 radian

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1.25 radian

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1.57 radian

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Similar questions

y_{1} = a s i n (ω t + k x + 0.57) m

y_{2} = a c o s (ω t + k x) m

x

t

y_{1} = 10^{- 6} sin [100 t + (x / 50) + 0.5] m

y_{2} = 10^{- 6} cos [100 t + (x / 50)] m

x

t

π = 3.14

y_{1} = a sin ω t

y_{2} = a cos ω t

y_{1} = A sin (ω t - k x + ϕ_{1})

y_{2} = A sin (ω t - k x + ϕ_{2})

A

(ϕ_{1} > ϕ_{2})

y_{1} = A sin (ω t - k x + ϕ_{1})

y_{2} = A sin (ω t - k x + ϕ_{2})

A

(ϕ_{1} > ϕ_{2})

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