Two waves are represented by the equations y 1- a sin - t - kx -0-57 m and y 2- a cos - t - kx m where x is in meter and t in s- The phasedifference between them isA- 1-0 radianB- 0-57 radianC- 1-25 radianD- 1-57 radian

The correct option is A 1.0 radiany_2=a sin(ω t+kx+π/2 ) y_1=a sin(ω t+kx+0.57 ) Phase difference =(π/2 0.57 )=1 radian ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Mechanical & Non-Mechanical Waves

Two waves are...

Question

Two waves are represented by the equations $y_{1} = a s i n (ω t + k x + 0.57) m$ and $y_{2} = a c o s (ω t + k x) m$ where x is in meter and t in s. The phase difference between them is

0.57 radian

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.0 radian

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.25 radian

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.57 radian

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

y_{1} = a s i n (ω t + k x + 0.57) m

y_{2} = a c o s (ω t + k x) m

x

t

y_{1} = 10^{- 6} sin [100 t + (x / 50) + 0.5] m

y_{2} = 10^{- 6} cos [100 t + (x / 50)] m

x

t

π = 3.14

y_{1} = a sin ω t

y_{2} = a cos ω t

y_{1} = A sin (ω t - k x + ϕ_{1})

y_{2} = A sin (ω t - k x + ϕ_{2})

A

(ϕ_{1} > ϕ_{2})

y_{1} = A sin (ω t - k x + ϕ_{1})

y_{2} = A sin (ω t - k x + ϕ_{2})

A

(ϕ_{1} > ϕ_{2})

Join BYJU'S Learning Program