Two waves interfere at a point- Vibrations due to the waves at that point can be represented by y 1-4 sin- t and y 2-3 sin- t -3- The amplitude of the resulting wave is nearlyA- 4B- 3C- 5D- 6

The correct option is D 6 Resultant amplitude due to interference is given by A=√(A_1^2+A_2^2+2A_1A_2cosϕ) where ϕ is the phase angle between the waves at the ...

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Byju's Answer

Standard XII

Physics

Interference General Case

Two waves int...

Question

Two waves interfere at a point. Vibrations due to the waves at that point can be represented by $y_{1} = 4 sin ω t$ and $y_{2} = 3 sin (ω t + \frac{π}{3})$ . The amplitude of the resulting wave is nearly

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Solution

The correct option is D 6

Resultant amplitude due to interference is given by
$A = \sqrt{A_{1}^{2} + A_{2}^{2} + 2 A_{1} A_{2} cos ϕ}$
where $ϕ$ is the phase angle between the waves at the point.
$\Rightarrow A = \sqrt{16 + 9 + 2 \times 4 \times 3 cos \frac{π}{3}}$
$\Rightarrow A = \sqrt{37} \approx 6$

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Two waves interfere at a point. Vibrations due to the waves at that point can be represented by y1=4sinωt and y2=3sin(ωt+π3). The amplitude of the resulting wave is nearly

The correct option is D 6 Resultant amplitude due to interference is given by A=√A21+A22+2A1A2cosϕ where ϕ is the phase angle between the waves at the point. ⇒A=√16+9+2×4×3cosπ3 ⇒A=√37≈6

Two waves interfere at a point. Vibrations due to the waves at that point can be represented by $y_{1} = 4 sin ω t$ and $y_{2} = 3 sin (ω t + \frac{π}{3})$ . The amplitude of the resulting wave is nearly