Two waves of frequencies 20 Hz and 30 Hz travels out from a common point. The phase difference between them after 0.6 sec is

12 π

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\frac{π}{2}

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π

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\frac{3 π}{4}

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Solution

The correct option is A $12 π$
Beats period $= \frac{1}{30 - 20} = 0.1 s e c o n d Δ Y = \frac{2 π}{T} Δ t = \frac{2 π}{0.1} \times 0.6 = 2 π \times 6 = 12 π ∴ Δ Y = 12 π$

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Two waves of frequencies 20 Hz and 30 Hz travels out from a common point. The phase difference between them after 0.6 sec is

The correct option is A 12πBeats period=130−20=0.1secondΔY=2πTΔt=2π0.1×0.6=2π×6=12π∴ΔY=12π

The correct option is A $12 π$
Beats period $= \frac{1}{30 - 20} = 0.1 s e c o n d Δ Y = \frac{2 π}{T} Δ t = \frac{2 π}{0.1} \times 0.6 = 2 π \times 6 = 12 π ∴ Δ Y = 12 π$