Two waves of same frequency but amplitudes equal to a and 2a travelling in the same direction superimpose out of phase. The resultant amplitude will be
A
√a2+2a2
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B
3a
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C
2a
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D
a
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Solution
The correct option is Da The amplitude of the resultant wave is x′0=√a2+(2a)2+2a×2acos(ϕ), here the angle between the two propagating waves is ϕ=π. Hence x′0=√a2+(2a)2+2a×2acos(π)=√a2+(2a)2−2a×2a=a