Two waves represented by equation, y1=2sin(πt−0.1x) and y2=2sin(πt−0.1x+ϕ) are superimposed. If the resultant wave has a maximum amplitude equal to 4cm, the value of ϕ is :
A
π
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B
2π
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C
π2
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D
3π2
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Solution
The correct option is B2π The phase difference between the given waves is, Δϕ=(πt−0.1x+ϕ)−(πt−0.1x) Δϕ=ϕ The maximum amplitude of resultant wave suggests that the waves have interfered constructively. ⇒Δϕ=2nπ The phase difference between waves is an integral multiple of 2π For n=1, ⇒Δϕ=ϕ=2π