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Question

Two waves represented by y1=3sin(2000πt50x) and
y2=3sin(2008πt+50x) are approaching each other. The number of beats heard per second will be
(Assume SI units)

A
8 Hz
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B
4 Hz
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C
1 Hz
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D
5 Hz
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Solution

The correct option is B 4 Hz
Given:
y1=3sin(2000πt50x)
y2=3sin(2008πt+50x)
Frequency of the first wave,
f1=ω12π=2000π2π=1000 Hz
and for the second wave,
f2=ω22π=2008π2π=1004 Hz
Now, beat frequency,
fb=|f1f2|=4 Hz
4 beats per second.

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