Two waves represented by $y$ = $a s i n (w t - k x)$ and $y$ = $a c o s (w t - k x)$ are superposed. The resultant wave will have an amplitude

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$\sqrt{2} a$

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Solution

The correct option is B
$\sqrt{2} a$

The phase diff between two waves = $\frac{π}{2}$

$\Rightarrow$ $A$ = $\sqrt{a^{2} + a^{2} + 2 a^{2} c o s \frac{π}{2}}$ = $\sqrt{2} a$

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Similar questions

Two waves represented by $y$ = $a s i n (w t - k x)$ and $y$ = $a c o s (w t - k x)$ are superposed. The resultant wave will have an amplitude

y = a s i n (ω t - k x)

y = a c o s (ω t - k x)

y_{1} = 5 sin (w t - k x)

y_{2} = - 5 cos (w t - k x - 30^{\circ}

y_{1} = 5 sin (w t - k x)

y_{2} = - 5 cos (w t - k x - 150^{o})

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