Two weights $w_{1}$ and $w_{2}$ are suspended to be the two strings on a frictionless pulley. When the pulled up with an acceleration g then the tension in the string is?

\frac{4 w_{1} w_{2}}{w_{1} + w_{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{w_{1} w_{2}}{w_{1} + w_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 w_{1} w_{2}}{w_{1} + w_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{w_{1} + w_{2}}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{4 w_{1} w_{2}}{w_{1} + w_{2}}$
The free body diagram of the given situation is shown. Taking the upward and downward motions respectively, we get
$T_{1} - m g = m_{1} (g + a)$
$T - 2 m g = m_{1} a$
for second weight
$m_{2} g - T = m_{2} (g - a)$
$2 m_{2} g - T = m_{2} a$
$T = \frac{4 m_{1} m_{2} g}{(m_{1} + m_{2})}$
$w_{1} = m_{1} g, m_{2} = m_{2} g$ hence switch
$T = \frac{4 w_{1} w_{2}}{(w_{1} + w_{2})}$ .

Suggest Corrections

Similar questions

Q. Two weights

w_{1}

and

w_{2}

are suspended to the two ends of a string passing over a smooth pulley. If the pulley is pulled up with an acceleration

g

, then the tension in the string is:

Q. Two weights

w_{1}

and

w_{2}

are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up at an acceleration g, what will be the tension in the string?

Q. Two weights

w_{1}

and

w_{2}

are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up at an acceleration

g

, the tension in the suspension of pulley will be:

Q. Two weights

w_{1}

and

w_{2}

are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up at an accelerating g, the tension in the string will be

A 100 W bulb $B_{1}$ , and two 60 W bulbs $B_{2}$ and $B_{3}$ , are connected to a 250 V source as shown in the figure. Now $W_{1}, W_{2}$ and $W_{3}$ are the output powers of the bulbs $B_{1}, B_{2}$ and $B_{3}$ respectively. Then

Join BYJU'S Learning Program

Two weights w1 and w2 are suspended to be the two strings on a frictionless pulley. When the pulled up with an acceleration g then the tension in the string is?

The correct option is B 4w1w2w1+w2The free body diagram of the given situation is shown. Taking the upward and downward motions respectively, we getT1−mg=m1(g+a)T−2mg=m1afor second weightm2g−T=m2(g−a)2m2g−T=m2aT=4m1m2g(m1+m2)w1=m1g,m2=m2g hence switchT=4w1w2(w1+w2).

Two weights $w_{1}$ and $w_{2}$ are suspended to be the two strings on a frictionless pulley. When the pulled up with an acceleration g then the tension in the string is?