Two wire A and B have equal lengths and are made of the same material, but the diameter of A is twice that of wire B. Then, for given load
A
The extension of B will be four times that of A
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B
the extension of A and B will be equal
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C
the strain in B is four times that in A
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D
the strains in A and B will be equal
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Solution
The correct options are A The extension of B will be four times that of A C the strain in B is four times that in A Δl=FLAY Thus, extension is inversely proportional to area, and also Strain=Δll is inversely proportional to area. Thus strain in B will be 4 times that in A since diameter of B is half of A, or area of B is one-fourth of A; and similar for extensions.