Two wires A and B are formed from the same material and same mass. Diameter of B is twice of A. If the resistance of wire A is 32 ohm.. find the resistance of wire B!
a and b are two wires.
We know, R =ρ l/A
Given, Da =Db/2 = ra=rb/2 (r is radius of wire)
so, Aa = Ab/4
Ab = 4Aa
and lb =la/4
Now, Rb =ρ lb/Ab
Rb =ρ (la/4) / 4Aa
= ρ la/Aa(1/16)
Given, (Ra =32Ω = ρ la/Aa )
So, Rb = 32/16 = 2 Ω