Two wires A and B have the same length and area of cross section. But Young’s modulus of A is two times the Young’s modulus of B. Then the ratio of force constant of A to that of B is

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Solution

The correct option is B 2
Force constant of wire $k = \frac{Y A}{L} \Rightarrow \frac{k_{A}}{k_{B}} = \frac{Y_{A}}{Y_{B}} = 2$ [As L and A are same]

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Two wires A and B have the same length and area of cross section. But Young’s modulus of A is two times the Young’s modulus of B. Then the ratio of force constant of A to that of B is

The correct option is B 2Force constant of wire k=YAL⇒kAkB=YAYB=2 [As L and A are same]

The correct option is B 2
Force constant of wire $k = \frac{Y A}{L} \Rightarrow \frac{k_{A}}{k_{B}} = \frac{Y_{A}}{Y_{B}} = 2$ [As L and A are same]