Question

Two wires A and B have the same length and area of cross section. But Young’s modulus of A is two times the Young’s modulus of B. Then the ratio of force constant of A to that of B is

• A. 1
• B. 2
• C. $\frac{1}{2}$
• D. $\sqrt{2}$

Answer 1

The correct option is B 2

Force constant of wire $k=\frac{YA}{L}\Rightarrow \frac{k_A}{k_B}=\frac{Y_A}{Y_B}=2$ [As L and A are same]