Question

Two wires $A$ and $B$ of same dimensions are stretched by same amount of force. Young's modulus of $A$ is twice that of $B$. Which wire will get more elongation? Enter 1 for A and 2 for B.

Answer 1

Youmng's modulus $=\frac{longitudinalstress}{longitudinalstrain}$
i.e, $Y=\frac{F/A}{\Delta l/l}$

$\Delta l=\frac{Fl}{AY}$

$\therefore \Delta l\propto \frac{1}{Y}$

As $Y_A=2Y_B$ so B has more elongation $\left(\Delta l\right)$