Two wires A and B of same matel have the same area of cross section and have their lengths in the ratio 2:1. What will be the ratio of currents flowing through them, when the same pottential difference is applied across length of each of them ....??

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Solution

given :

.ratio of lengths = 2:1

.both the wires have same cross sectional area

.Same potential difference is applied

as we know that , V = IR ............(1)
here, V = POTENTIAL DIFFERENCE
I = CURRENT
R= RESISTANCE
to find the ratio of current flowing through them .
by using (1) :
I = V / R
so , ratio of potential difference = R2 / R1
I1 / I2 = R2 / R1
here, I1 ,I2 and R1 and R2 are the current and resistance of 1st and 2nd wire respectively.
= 1:2

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