Two wires A and B of the same material have their lengths in the ratio 1:2 and radii in the ratio 3:1. The two wires are connected in parallel across a battery. The ratio of heat produced in A to the heat produced in B for the same time is-
1:18
let lengths of A and B be 1x and 2x respectively, and radii of A and B be 3y and 1y respectively.
Resistance of a wire is given as
R=ρLAρ=resistivityL=length A=cross sectional area
As the material is same, resistivity remains unchanged
RA=ρ1x∏(3y)2RB=ρ2x∏(1y)2