Two wires AC and BC are tied at C of small sphere of mass 5 kg, which revolves at a constant speed v in the horizontal circle of radius 1.6 m. Find the minimum value of v.
4 m/s
From for diagram shown in figure,
T1 cos 30∘+T2 cos 45∘=mg ........(i)
T1 sin 30∘+T2 sin 45∘=mv2r ........(ii)
After solving equation (i) and (ii), T1=mg − mv2r(√3 − 1)2
But T1>0,mg − mv2r(√3 − 1)2>0⇒mg>mv2r,v<√rg
v min = √1.6×10 = 4 m/s