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Question

Two wires are made up of the same material and have the same volume. However wire 1 has a cross-sectional area A and wire 2 has a cross-sectional area 3 A. If the length of the wire 1 increases by dx on applying force F, how much force is needed to stretch wire by the same amount?

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Solution

Force for stretching the wire is propotional tocross sectional Area(A) of wire andinversly propotional to strain(dl/l) F1F2=A1l1A2l2 -(1)Given A1=A, A2=3A,l1=dx,l2=dx(increament in length)Using (1) we get F2 =3F1

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