Two wires of equal length and cross-section are suspended as shown. Their Young’s modulii are y1 and y2 respectively. The equivalent Young’s modulus will be
A
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B
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C
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D
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Solution
The correct option is B Let the equivalent young's modulus of given combination is Y and the area of cross section is 2A. For parallel combination k1+k2=keq. Y1AL+Y2AL=Y2AL Y1+Y2=2Y,∴Y=Y1+Y22