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Question

Two wires of the same material and length are stretched by the same force. Their masses are in the ratio 3:2. Then, their elongations will be in the ratio :


A
3:2
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B
9:4
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C
2:3
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D
4:9
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Solution

The correct option is B 2:3
We know, Y=FLAΔL
Given F,L and Y are constant
Hence,  ΔL1A
As we know,
Mass=Volume×density
m=(A×L)×ρ
[Same material, hence ρ = constant]
or, mA
ΔL1m
ΔL1ΔL2=m2m1=23

Physics

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