Question

# Two wires of the same material and length are stretched by the same force. Their masses are in the ratio 3:2. Then, their elongations will be in the ratio :

A
3:2
B
9:4
C
2:3
D
4:9

Solution

## The correct option is B 2:3We know, Y=FLAΔL Given F,L and Y are constant Hence,  ΔL∝1A As we know, Mass=Volume×density m=(A×L)×ρ [Same material, hence ρ = constant] or, m∝A ∴ΔL∝1m ΔL1ΔL2=m2m1=23Physics

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