Two workers C and D working together completed a job in 20 days. If C worked twice as efficiently than he actually did and D worked 43rd as efficiently than he actually did, the work would have been completed in 12 days. If they get a total of Rs.360 for completing the work, what is C's share?
Rs.180
Let C’s 1 day’s work = ‘x’ & D’s 1 day’s work = ‘y’.
Then, x+y = 120 and 2x+43y = 112
Solving, we get x = 140 and y = 140
∴C′s share = 3602 = Rs.180