Two wrestler A and B as shown are pushing eachother in opposite direction with the force of 50 N. Find the net force on the wrestler A.

0 N, no movement.

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100 N in left direction.

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100 N in right direction.

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50 N in left direction.

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Solution

The correct option is A 0 N, no movement.
As two wrestler A and B are pushing each other, we can take the direction of force applied by wrestler A to be positive.
So, taking right direction to be positive:
$N e t f o r c e = F_{A} + F_{B} = (+ 50) + (- 50) = 50 - 50 = 0 N$
As the net force on wrestler A is zero, there will be no movement.

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