Two wrestlers A and B as shown are pushing each other in opposite directions with a force of 50 N each. Find the net force on the wrestler A.

100 N in left direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0 N, no movement

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

50 N in left direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100 N in right direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 0 N, no movement
As the two wrestlers A and B are pushing each other, we can take the direction of force applied by wrestler A to be positive.
So, taking right direction to be positive:
$N e t f o r c e = F_{A} + F_{B} = (+ 50) + (- 50) = 50 - 50 = 0 N$
As the net force on wrestler A is zero, there will be no movement.

Suggest Corrections

Similar questions

Q. Solve the following numerical problems.
Two persons are pushing a car with a force of

30 N

and

70 N

in opposite directions. Calculate the resultant force and its direction.

two forces while acting on a paricle in opposite directions , have the resultant of 10 N . if they act at right to each other , the resultant is found to be 50 N. Find the two forces.

Q. In the given diagram, a person is pushing a box on a rough surface. Identify the pair of forces acting on the box in opposite directions to each other.

Q. Two forces, while acting on a particle in opposite; directions, have the resultant of

10 N

. If they act at right angles to each other, the resultant is found to be

50 N

. Find the two forces.

Q. Two boys are pushing a box with a force of 50 N each. Which of the following options correctly explains the given scenario.

Join BYJU'S Learning Program